MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mole Concept

a sugar syrup...

Question

a sugar syrup of weight 214.2 g contains 34.2 g sugar ( C12 H22 O11 ) . calculate mole fraction of sugar in syrup.

Open in App

Solution

Mass of syrup = 214.2 g
Mass of sugar =34.2 g

Molar mass of sugar = 342 g/ mol

No. of moles of sugar (n_A) =34.2/342 = 0.1 mole

Mass of water in sugar syrup = 214.2-34.2 = 180 g

No. of moles of water(n_B) = 180/18 =10 moles

Mole fraction of sugar (x_A) = n_A/ (n_A + n_B) =0.1/ (0.1 +10) =0.1 /10.1 =0.0099

Suggest Corrections

thumbs-up

1

Similar questions

Q. A sugar syrup (containing sugar and water only) of weight 214.2 g contains 34.2 g of sugar (

C_{12} H_{22} O_{11}

). Find the mole fraction of the sugar in the syrup.

Q. 214.2 g of sugar syrup contains 34.2 g of sugar.

(i) molarity of the solution

(ii) mole fraction of sugar in the syrup.

Q. A sugar syrup of weight

214.2

34.2

(C_{12} H_{22} O_{11})

. Calculate the mole fraction of the sugar in the syrup.

(If the answer is X, then write

\frac{1000}{11}

Q. A sugar syrup of weight

214.2

34.2

(C_{12} H_{22} O_{11})

. Calculate. the molal concentration (Write your answer as 18X, where, X= molality)

Q. A sugar syrup (containing sugar and water only) of weight 214.2 g contains 34.2 g of sugar (

C_{12} H_{22} O_{11}

). Find the mole fraction of the sugar in the syrup.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Mole and Mass

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon