CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pulley

A woman weigh...

Question

A woman weighing 50 kg stands on a weighing machine placed in a lift. What will be the reading of the machine in the following cases ?1) when a lift is moving upward with a uniform velocity of 5m/s.2) when the lift is moving downwards with a uniform accelartion of 1m/s. [g=10 m/s^2]

Open in App

Solution

Mass of woman, M=50 kg
(1) When lift is inn uniform motion ,acceleration of woman ,a=0
apparent wight = actual weight
Reading of machine , R= Mg = $50 k g \times 10 m / s^{2} = 500 N$ or 50kg wt.

(2) When lift is moving downwards with uniform acceleration 1m/s² (say a)
Apparent weight is less than actual weight
Reading of machine ,R =M(g-a)= $50 (10 - 1) = 450 N$ or 45kg wt.

Suggest Corrections

thumbs-up

0

Similar questions

Q. A Woman weighing 50 kg stands on a weighting machine placed in a lift. What will be the reading of the machine, When the lift is (i) moving upwards with a uniform velocity of

5 m s^{- 1}

and (ii) moving downwards with a uniform acceleration of

1 m s^{- 2} ?

[T a k e

g = 10 m s^{- 2}] .

Q. A person weighs

60 k g

. He stands on a weighing machine in a lift which is moving.
(i) upward with uniform speed

5 m / s

.
(ii) downward with a uniform acceleration

4 m / s^{2}

.
(iii) upward with a uniform acceleration

4 m / s^{2}

.
What would be the reading on the scale in each case?
(Take

g = 10 m / s^{2}

Q. A man weighs 80 kg He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of

5 m / s^{2} .

What would be the reading on the scale ?

(g = 10 m / s^{2})

Q. A spring weighing machine inside a stationary lift reads 50 kg when a man stands on it. What would happen to the scale reading if the lift is moving upward with (i) constant velocity, and (ii) constant acceleration?

Q. A man is standing on a weighing machine placed in a lift. When stationary, his weight is recorded as

40 k g

. If the lift is accelerated upward with an acceleration of

2 m / s^{2}

, then the weight recorded in the machine will be

g = 10 m / s^{2}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

What's with All the Tension in the Room?

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon