An electric bulb of resistance 20ohm and a resistance wire of 4ohm are connected in series with a 6v battery. Calculate the total resistance of the circuit and the potential difference across electric bulb and resistance wire?

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Solution

$T o t a l r e s i s \tan c e o f t h e c i r c u i t i s R 20 + 4 = 24 o h m . V o l a t g e i n t h e c i r c u i t = 6 v c u r r e n t i n t h e c i r c u i t I = \frac{v}{R} = \frac{6}{24} = 0.25 A w e k n o w i n s e r i e s c u r r e n t r e m a i n s s a m e b u t v o l t a g e i s d i f f e r e n t . v o l t a g e a c r o s s t h e b u l b = r e s i s \tan c e o f t h e b u l b \times c u r r e n t = 20 \times 0.25 = 5 v o l t v o l t a g e a c r o s s t h e w i r e = r e s i s \tan c e o f t h e w i r e \times c u r r e n t = 4 \times 0.25 = 1 v o l t$

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Q. An electric bulb of resistance 20 Ω and a resistance wire of 4 Ω are connected in series with a 6 V battery.
Draw the circuit diagram, and calculate:

(a) total resistance of the circuit.
(b) current through the circuit.
(c) potential difference across the electric bulb.
(d) potential difference across the resistance wire.

An electric bulb of resistance $20 Ω$ and a a resistance wire of $4 Ω$ are connected in series with a 6 V battery.
(a) Total resistance of the circuit.
(b) Current through the circuit.
(c) Potential difference across the electric bulb.
(d) Potential difference across the resistance wire.