an object is dropped from height h when is its a. potential energy maximum b. kinetic energy maximum c.potential energy=kinetic energy

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Solution

maximum potential energy will be at height h where its kinetic energy is zero.=mgh
maximum kinetic energy will be at height 0 or at ground where its potential energy is zero.=mv²/2
potential energy=kinetic energy
mgh'=mv'²/2
h'=v'²/2g
v'=velocity at height h'

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