$p$ and $q$ are in ............ proportion
$p$ $1$ $2$ $3$ $4$
$q$ $3$ $7$ $11$ $12$

direct

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indirect

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both

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none

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Solution

The correct option is D none
$\frac{p}{q} = \frac{1}{3} \neq \frac{2}{7} \neq \frac{3}{11} \neq \frac{4}{12} \neq c o n s t a n t$
$p \times q = 1 \times 3 \neq 2 \times 7 \neq 3 \times 11 \neq 4 \times 12 \neq c o n s t a n t$

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Similar questions

(a) Subtract 4a − 7ab + 3b + 12 from 12a − 9ab + 5b − 3

(b) Subtract 3xy + 5yz − 7zx from 5xy − 2yz − 2zx + 10xyz

4 a - 7 a b + 3 b + 12

12 a - 9 a b + 5 b - 3

3 x y + 5 y z - 7 z x

5 x y - 2 y z - 2 z x + 10 x y z

4 p^{2} q - 3 p q + 5 p q^{2} - 8 p + 7 q - 10

18 - 3 p - 11 q + 5 p q - 2 p q^{2} + 5 p^{2} q

$Subtract$ $4 p^{2} q - 3 p q + 5 p q^{2} - 8 p + 7 q - 10$ $from$
$18 - 3 p - 11 q + 5 p q - 2 p q^{2} + 5 p^{2} q$

\frac{2 \sqrt{3} - 7 \sqrt{2}}{\sqrt{11} - \sqrt{3} + 2 \sqrt{2}} = p + q \sqrt{6} + r \sqrt{22} + s \sqrt{33},

[4 r - \frac{12}{7} s + \frac{12}{17} q - \frac{4}{11} p]

\frac{2 \sqrt{3} - 7 \sqrt{2}}{\sqrt{11} - \sqrt{3} + 2 \sqrt{2}} = p + q \sqrt{6} + r \sqrt{22} + s \sqrt{33},

[4 r - \frac{12}{7} s + \frac{12}{17} q - \frac{4}{11} p]

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