As you have learnt inthe text- a geostationary satellite orbits the earth at a height ofnearly 36-000 km from the surface of the earth- What is the potentialdue to earth rsquo-s gravity at the site of this satellite- -Take thepotential energy at infinity to be zero- Mass of the earth - 6-0 times- 1024kg- radius - 6400 km-

Mass of the Earth, M= 6.0 times; 1024 kgRadius of the Earth, R= 6400 km = 6.4 times; 106 mHeight of ageostationary satellite from the surface of the Earth ...

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Standard IX

Physics

Universal Law of Gravitation

As you have l...

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As you have learnt inthe text, a geostationary satellite orbits the earth at a height ofnearly 36,000 km from the surface of the earth. What is the potentialdue to earth’s gravity at the site of this satellite? (Take thepotential energy at infinity to be zero). Mass of the earth = 6.0× 10²⁴kg, radius = 6400 km.

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Solution

Mass of the Earth, M= 6.0 × 10²⁴ kg
Radius of the Earth, R= 6400 km = 6.4 × 10⁶ m
Height of ageostationary satellite from the surface of the Earth,
h = 36000 km =3.6 × 10⁷ m
Gravitational potentialenergy due to Earth’s gravity at height h,

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Mass of the Earth, M= 6.0 × 1024 kgRadius of the Earth, R= 6400 km = 6.4 × 106 mHeight of ageostationary satellite from the surface of the Earth, h = 36000 km =3.6 × 107 mGravitational potentialenergy due to Earth’s gravity at height h,

Mass of the Earth, M= 6.0 × 10²⁴ kg
Radius of the Earth, R= 6400 km = 6.4 × 10⁶ m
Height of ageostationary satellite from the surface of the Earth,
h = 36000 km =3.6 × 10⁷ m
Gravitational potentialenergy due to Earth’s gravity at height h,