a. A ship has to reach a place 15° South of West, with respect to its starting point. The declination of the starting point is 19° West.

In what direction should the ship be steered?

b. A magnet suspended at 30° with the magnetic meridian makes an angle of 40° with the horizontal.

What should be the actual value of the angel of dip?.

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Solution

Answer to part (b)

we know that
tanÎ¸ = V / HcosÎ±
and
Î¸ = 40
Î± = 30
so.
tan40 = V / Hcos30
or
V = 0.84Hcos30

and also angle of dip is
tanÎ´ = V/H
or
tanÎ´ = 0.84Hcos30 / H
or
tanÎ´ = 0.84Cos30

thus, the angle of dip will be
Î´ = tan^-1 (0.727) = 36.01^o

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Answer to part (b) we know thattanÎ¸ = V / HcosÎ±andÎ¸ = 40Î± = 30so.tan40 = V / Hcos30orV = 0.84Hcos30 and also angle of dip istanÎ´ = V/HortanÎ´ = 0.84Hcos30 / HortanÎ´ = 0.84Cos30 thus, the angle of dip will be Î´ = tan-1 (0.727) = 36.01o

Answer to part (b)

we know that
tanÎ¸ = V / HcosÎ±
and
Î¸ = 40
Î± = 30
so.
tan40 = V / Hcos30
or
V = 0.84Hcos30

and also angle of dip is
tanÎ´ = V/H
or
tanÎ´ = 0.84Hcos30 / H
or
tanÎ´ = 0.84Cos30

thus, the angle of dip will be
Î´ = tan^-1 (0.727) = 36.01^o