Calculate cell potential of the following cellZn-s- - Zn2- - Pb2- - Pb-s-Given E -9675-Pb-Pb2-0-12V- E -9675-Zn-Zn2-0-76V

Half cell reactions for the given cell: Zn #160; #8594;Zn2+ #160;+ #160;2ePb2+ #160;+ #160;2e #160; #8594;Pb nbsp; Ecell #160;= #160;oxid ...

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Secondary Cells

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Question

Calculate cell potential of the following cell
Zn_(s) | Zn²⁺ || Pb²⁺ | Pb_(s)
Given E^○_Pb/Pb²⁺=+0.12V, E^○_Zn/Zn²⁺=+0.76V

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E_{(P b^{2 +} | P b)}^{⊖} = - 0.126 V, E_{(Z n^{2 +} | Z n)}^{⊖} = - 0.763 V

25^{\circ} C

Z n | Z n^{2 +} (1 M) | | P b^{2 +}

P b^{2 +}

P b^{2 +}

2.5 \times 10^{- x} M

△ G^{\circ}

Z n (s) + A g_{2} O (s) + H_{2} O (l) ⇌ Z n^{2 +} (a q) + 2 A g (s) + 2 O H^{-} (a q)

E_{A g^{+} / A g}^{\circ} = + 0.80 V

E_{Z n^{2 +} / Z N}^{\circ} = - 0.76 V

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2 A g + Z n^{2 +} \to 2 A g^{+} + Z n

E_{A g^{+} / A g}^{\circ} = 0.80 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

Zn {(N O_{3})}_{2}

Pb {(N O_{3})}_{2}

E_{Z n^{2 +}, Z n}^{\circ} = - 0.76 V, E_{P b^{2 +}, P b}^{\circ} = 0.13 V

Z n | {Z n}^{2 +} (0.1 M) ∥ {P b}^{2 +} (1 M) | P b

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