calculate the bond order of He2+
As each Helium atom contains 2 electrons, the number of electrons in He2+ ion will be 3. Two electrons will enter the bonding
σ(1s) molecular orbital and the third electron will enter the antibonding σ*(1s) molecular orbital. Thus electronic configuration of He2+ will be:
[σ(1s)]2[σ*(1s)]1
Here, Nb( electron in bonding orbital) = 2
Na (elelctron in antibonding orbital) = 1
Bond order = 1/2 ( Nb - Na )
bond order = 1/2 (2-1)
bond order = 1/2