Question

CALCULATE THE FOLLOWING QUANTITIES IN 5.6 G OF NITROGEN GAS :

a)NO.OF MOLES OF NITROGEN

b)NO ,OF ATOMS OF NITROGEN

(atomic mass , N=14u)

Answer 1

Part : I

Nitrogen exit as gas molecule : N₂

Molar Mass of N₂ gas = 2 x14 = 28 g

No. of Mole = Amount of gas / Molar Mass = 5.6/28 = 0.2 moles.

Part : II

No. of Atoms = No. of Mole x N_A = 0.2 x 6.022 x10²³

= 0.2 x 6.022 x 10²³

= 12.044 x 10²²

(N_A= Avagrado's Number = 6.022 x 10²³)