Calculate the ratio of atoms present in 5g of magnesium and 5g of iron.

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Solution

The molar mass of magnesium is 24 g. We know that one mole of a substance contains 6.023 X 10²³ particles. Therefore
number of atoms present in 24g of Mg = 6.023 X 10²³
number of atoms present in 1 g of Mg = (6.023 X 10²³) / 24
number of atoms present in 5g of Mg = (6.023 X 10²³ X 5) / 24
= 12.547 X 10²²

The molar mass of iron is 56g. Therefore
number of atoms present in 56g of Fe = 6.023 X 10²³
number of atoms present in 1 g of Fe = (6.023 X 10²³) / 56
umber of atoms present in 5g of Fe = (6.023 X 10²³ X 5) / 56
= 5.377 X 10²²
So, the ratio of atoms in 5g of Mg and 5g of Fe is
= 12.547 X 10²² / 5.377 X 10²²
= 2.333

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