calculate the ratio of partial positive charge on H-atom in HCL to that in HI from the following data;
dipole moment of HCL = 1.03 D , Bond Length = 127 pm dipole moment of HI = .38 D Bond length = 161 pm>
Dear student!
Dipole moment = charge x bond length
Putting the values for HCl,
q = μ / d
Since, 1D = 10-18 esu cm
1 nm = 10-7 cm
So, q = 1.03 x 10-18 esu cm / 127 x 10-7 cm = 8.11 x 10-14 esu
Similarly for HI,
1 pm = 10-10 cm
q = 0.38 x 10-18 esu cm / 161 x 10-10 cm = 2.36 x 10-11 esu.