Chlorine has two isotopes of atomic mass 34.91 36.97 .What is relative abunduance of each isotope if the average atomic mass is 35.49.

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Solution

Let the relative abundance of Cl-35be x.
thus relative abundance of Cl-37 be 100-x

35.49= [(34.91x)+(36.97(100-x))]/100
2.06 x = 148
x=74 %
Thus Cl -35 is approx 74%
Cl-37 is approx 26%

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Chlorine has two isotopes of atomic mass 34.91 36.97 .What is relative abunduance of each isotope if the average atomic mass is 35.49.

Let the relative abundance of Cl-35be x.thus relative abundance of Cl-37 be 100-x 35.49= [(34.91*x)+(36.97*(100-x))]/1002.06 x = 148x=74 % Thus Cl -35 is approx 74%Cl-37 is approx 26%

Let the relative abundance of Cl-35be x.
thus relative abundance of Cl-37 be 100-x

35.49= [(34.91x)+(36.97(100-x))]/100
2.06 x = 148
x=74 %
Thus Cl -35 is approx 74%
Cl-37 is approx 26%