Compare the pressure exerted by a person standing on the ground on one foot and when he is standing on both the feet. Assume that the area of each foot is 0.04 m2 and the mass of the person is 40 kg. Take g= m/s²

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Solution

Given, Area of one foot $=$ 0 $\cdot$ 04 m²
Area of two feet $=$ 2 $\times$ 0 $\cdot$ 04 m²
Mass of person $=$ 40kg
Weight of person = mg = 40 X 9.8 N = 392 N
As, we know the force of attraction of earth on a body is known as the weight of the body.
Since, pressure is given by :
P = F/A , where F is the force and A is the area of the body.
Pressure exerted when standing on one foot $=$ 392 $/$ 0 $\cdot$ 04 $=$ 9800 N $/$ m2
Pressure exerted when standing on both feet $=$ 392 $/$ ( 2 $\times$ 0 $\cdot$ 04) $=$ 4900 N $/$ m²
So the pressure exerted by man standing on one leg is twice the pressure exerted by him when he is standing on both feets.

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Compare the pressure exerted by a person standing on the ground on one foot and when he is standing on both the feet. Assume that the area of each foot is 0.04 m2 and the mass of the person is 40 kg. Take g= m/s2

Compare the pressure exerted by a person standing on the ground on one foot and when he is standing on both the feet. Assume that the area of each foot is 0.04 m2 and the mass of the person is 40 kg. Take g= m/s²