Compute the voltage drop across a 2 KW electric heater element whose resistance when hot is 20 ohm.

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Solution

P= V²/R
P= 2kW= 2000W
R= 20 ohm
2000 = V²/20
V² = 2000 x 20
V²= 40000
V= 200V

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Compute the voltage drop across a 2 KW electric heater element whose resistance when hot is 20 ohm.

P= V2/RP= 2kW= 2000WR= 20 ohm2000 = V2/20V2 = 2000 x 20V2= 40000V= 200V

P= V²/R
P= 2kW= 2000W
R= 20 ohm
2000 = V²/20
V² = 2000 x 20
V²= 40000
V= 200V