When a battery connected across a resistor of 16Ω, the voltage across the resistor is 12V. When the same battery is connected across a resistor of 10Ω, voltage across it is 11V. The internal resistance of the battery (in ohm) is:
A
107
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B
207
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C
257
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D
307
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Solution
The correct option is B207 Here, V<E ∴E=V+Ir For first case E=12+1216r ....(i) For second case E=11+1110r ....(ii) From equations (i) and (ii), 12+1216r=11+1110r ⇒r=207Ω