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Stability of Free Radical

E0 values for...

Question

E0 values for Mn3+/Mn2+ is much more positive than Cr3+/Cr2+ or Fe+3/Fe+2 couple. why?/////////

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Solution

This is because Mn ²⁺ (d⁵)is more stable as compare to Cr²⁺ (d⁴) and Fe²⁺(d⁶).

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Similar questions

Q. (a) Complete the following equations:
(i)

{C r}_{2} O_{7}^{2 -} + 2 O H^{-} \to

M n O_{4}^{-} + 4 H^{+} + 3 e^{-} \to

(b) Account for the following:
(i)

Z n

is not considered as a transition element.
(ii) Transition metals form a larger number of complexes.
(iii) The

E^{0}

{M n}^{3 +} / {M n}^{2 +}

couple is much more positive than that for

{C r}^{3 +} / {C r}^{2 +}

Q. Account for the following:
(i) In the series Sc to Zn, the enthalpy of atomisation of zinc is the lowest.
(ii)

E^{o}

M n^{3 +} / M n^{2 +}

couple is much more positive than that for

C r^{3 +} / C r^{2 +}

Q. Give reasons.

E^{o}

M n^{3 +} / M n^{2 +}

couple is much more positive than that for

F e^{3 +} / F e^{2 +}

.

E^{\circ}

M n^{3 +} / M n^{2 +}

is more positive than

C r^{3} / C r^{2 +}

. Reason: The third ionization energy of

M n

is larger than that of

C r

.

M^{2 +} / M

M^{3 +} / M^{2 +}

E^{⊖}

values for some metals are as follows:

$C r^{2 +} / C r$	$- 0.9 V$ $	$C r^{3} / C r^{2 +}$	$- 0.4 V$
$M n^{2 +} / M n$	$- 1.2 V$	$M n^{3 +} / M n^{2 +}$	$+ 1.5 V$
$F e^{2 +} / F e$	$- 0.4 V$	$F e^{3 +} / F e^{2 +}$	$+ 0.8 V$

Use this data to comment upon:
(i) the stability of

F e^{3 +}

in acid solution as compared to that of

C r^{3 +}

M n^{3 +}

and
(ii) the ease with which iron can be oxidised as compared to a similar process for either chromium or manganese metal

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