-For ice- the latent heat of fusion is 334 kJkg-1- This means that 334 kJ of heat is required to convert 1 kg of ice at 0-C into 1 kg of water at 0-C- Conversely- 334 kJ of heat is released when 1 kg of water freezes at 0-C to give 1 kg of ice at 0-C- So in this case 0oC is the atmospheric temp-

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"For ice, the...

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"For ice, the latent heat of fusion is 334 kJkg^-1. This means that 334 kJ of heat is required to convert 1 kg of ice at 0ºC into 1 kg of water at 0ºC. Conversely, 334 kJ of heat is released when 1 kg of water freezes at 0ºC to give 1 kg of ice at 0ºC." So in this case 0^oC is the atmospheric temp.?

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0^{0} C

{24.4}^{0} C

1 k g

= 336 k J / k g

Heat energy required to melt $10 k g$ ice at its melting point will be _____. (The latent heat of fusion of water = $333.55 k J k g^{- 1}$ ).

1

- 10^{0} C

100^{0} C

=

4.187

^{0}

=

334

=

2260

=

2.03

10 k g

0^{o} C

50^{o} C

4200 J / k g^{o} C

336 \times 10^{3} J / k g

0^{\circ} C

- 335 \times 10^{3} J / k g

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