From where does a person o a bike , while taking turn on a level road , get the necessary centripetal force?

Open in App

Solution

The frictional force between the tire and the road, and the gravity provides the necessary centripetal force to the car taking turn.

Suggest Corrections

Similar questions

Q. Statement I : On a banked curved road, vertical component of normal reaction provides the necessary centripetal force.
Statement II : Centripetal force is always required for turning on a curved path.

Q. The road at a circular turn of radius 10 m is banked by an angle of

10^{o}

, with what speed should vehicle move on the turn so that the normal contact force is able to provide the necessary centripetal force.[tan

10^{o}

=0.18]

Q. A small coin is placed on a record rotating at

33 \frac{1}{3}

rev/minute. The coin does not slip on the record. Where does it get the required centripetal force from?

Q. While turning on a banked frictionless surface, the centripetal force is

A car moving in a horizontal road may be thrown out of the road in taking a turn this is because of lack of centripetal force but why not friction between the road and tyre??

Join BYJU'S Learning Program