Give the relation between oxidation potentional and reduction potentional??

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Solution

E° = E° (oxidation) + E° (reduction).
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(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

How to convert oxidation potential to reduction potential?

K_{s p} (A g C l)

A g | A g C l (saturated) in K C l

If there is no mention of oxidation and reduction potential in the problem we assume it to be reduction potential. why?

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