1
Question
How do you explain theabsence of aldehyde group in the pentaacetate of D-glucose?
How do you explain theabsence of aldehyde group in the pentaacetate of D-glucose?
Open in App
Solution
D-glucose reacts withhydroxylamine (NH2OH) to form an oxime because of thepresence of aldehydic (−CHO) group or carbonyl carbon. Thishappens as the cyclic structure of glucose forms an open chainstructure in an aqueous medium, which then reacts with NH2OHto give an oxime.
But pentaacetate ofD-glucose does not react with NH2OH. This is becausepentaacetate does not form an open chain structure.
D-glucose reacts withhydroxylamine (NH2OH) to form an oxime because of thepresence of aldehydic (−CHO) group or carbonyl carbon. Thishappens as the cyclic structure of glucose forms an open chainstructure in an aqueous medium, which then reacts with NH2OHto give an oxime.
But pentaacetate ofD-glucose does not react with NH2OH. This is becausepentaacetate does not form an open chain structure.
Suggest Corrections
0
Similar questions