how does an inductor behave in an ac circuit after the current reaches to steady state?

Open in App

Solution

The inductor activate itself when current change in the the given circuit hence in when inductor connected across alternating current then it is always activated its one of the mains features is that it opposes the change of current in the circuit. hence it opposes the alternating current , but when current becomes constant or steady the inductor does not oppose the current since the value of current in circuit this time is constant.

Suggest Corrections

Similar questions

A coil of inductance 0.50 H and resistance

100 Ω

is connected to a 240 V, 50 Hz ac supply.

(a) What is the maximum current in the coil?

(b) What is the time lag between the voltage maximum and the current maximum?

Hence, explain the statement that at very high frequency, an inductor in a circuit nearly amounts to an open circuit. How does an inductor behave in a dc circuit after the steady state?

Obtain the answers (a) to (b) in Exercise 7.13 if the circuit is connected to a high frequency supply (240 V, 10 kHz). Hence, explain the statement that at very high frequency, an inductor in a circuit nearly amounts to an open circuit. How does an inductor behave in a dc circuit after the steady state?

Q. How does an inductor behave in a d.c circuit ?

Q. When an AC source is connected to a capacitor, there is a steady-state current in the circuit. Does it mean that the charges jump from one plate to the other to complete the circuit?

Q. Switch

S

is closed at

t = 0

, in the circuit shown. The change in flux in the inductor (

L = 500 m H

) from

t = 0

to an instant when it reaches steady state is :

Join BYJU'S Learning Program