Question

How many atoms of each element are there in 9.8gm of sulphuric acid?

Answer 1

Let us calculate number of atoms of each element in 9.8gm of sulphuric acid (H₂SO₄).

Molar mass of H₂SO₄ = 98g

Number of moles of H₂SO₄ in 9.8 gm of H₂SO₄ = 9.8/98 = 0.1 mole

Now 1 mole of H₂SO₄ = 6.022*10²³ molecules of H₂SO₄

0.1 mole of H₂SO₄ = 0.1 (6.022*10²³ molecules of H₂SO₄) = 6.022*10²² molecules of H₂SO₄

Now 1 molecule of H₂SO₄ contains 2,1 and 4 atoms of H, S and O respectively.

So number of hydrogen atoms in 6.022*10²² molecules of H₂SO₄ = 2(6.022*10²²)

So number of hydrogen atoms in 6.022*10²² molecules of H₂SO₄= 12.044*10²²

So number of sulphur atoms in 6.022*10²² molecules of H₂SO₄= 6.022*10²²

So number of oxygen atoms in 6.022*10²² molecules of H₂SO₄= 4(6.022*10²²)

So number of oxygen atoms in 6.022*10²² molecules of H₂SO₄= 24.088*10²²