Question

how many grams of sulphuric acid are present in 2l of 1.5 M H2SO4

Answer 1

Molarity of H₂SO₄ = $\frac{\mathrm{Mass}\mathrm{of}{\mathrm{H}}_2{\mathrm{SO}}_4}{\mathrm{Molar}\mathrm{mass}\mathrm{of}{\mathrm{H}}_2{\mathrm{SO}}_4\times \mathrm{Volume}\mathrm{of}\mathrm{solution}\mathrm{in}\mathrm{liters}}$

Molar mass of H₂SO₄ = 98g/mol
​Using molarity formula to find mass of sulphuric acid,
$$\begin{gathered} 1.5=\frac{\mathrm{Mass}\mathrm{of}{\mathrm{H}}_2{\mathrm{SO}}_4}{98\times 2} \\ \mathrm{Mass}\mathrm{of}{\mathrm{H}}_2{\mathrm{SO}}_4=294\mathrm{g} \end{gathered}$$