How much heat energy is required to change 100g of ice at -30^oC to water at 80^oC. (given: latent heat of fusion of ice=355kJ kg^-1,and specific heat of ice=2100J kg^-1^oC^-1,specific heat of water=4.2k J kg^-1^oC^-1)

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Solution

If Q₁= amount of sensible heat required to convert ice at -30^oC into water at 0⁰C (ice):-
Q₁₌mcΔt
=0.1 kg x (2100 J /kg^oC)X (80-(-30))⁰C
=23100 joule.
If Q₂₌Amount of latent heat required to convert water at 0⁰C into water at 80⁰C :-
Q_{2 =}mL
=0.1 kg x 355 kJ kg^-1=35,500 joule
Total heat = Q₁+ Q₂
=58600 joules

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