Question

How to factorize x -8xy³ on the basis of (x3 - y3) ?

Answer 1

Hi!

Here is the answer to your question.

x – 8xy³

= x (1 – 8y³)

= x [(1)³ – (2y)³]

= x (1 – 2y) [(1)² + 1 × (2y) + (2y)²] [ a³ – b³ = (a – b) (a² + ab + b²)]

= x (1 – 2y) (1 + 2y + 4y²)

Thus, x – 8xy³ can be factorized as x (1 – 2y) (1 + 2y + 4y²).

Cheers!