How to find structure and hybridization of
IO4-
Dear student!
To find the structure and hybridization of IO4- we take the following steps as:
Total no. of valence electrons = 7 (for I) + 4x6(for O) = 31
No. of ions = 1
So, total available electrons = 31+1=32
Total bond pairs = total no. of atoms -1 =5-1=4
Hybridization = sp3
Structure = Tetrahedral
Electrons consumed in bond formation = 8x4 = 32
So lone pair = 0
Hence, shape is same as structure i.e. tetrahedral.