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Question
how will you connect three resistors of resistors 2Ω , 3Ω and 6Ω to obtain a total resistance of 2.5 ? draw the diagram to show the arrangement .
how will you connect three resistors of resistors 2Ω , 3Ω and 6Ω to obtain a total resistance of 2.5 ? draw the diagram to show the arrangement .
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Solution
With the given resistances 2Ω , 3 Ω and 6 Ω,we can't obtain a total resistance of 2.5.
If the three resistors are connected in series,then R=2+3+6=11 ohm
If the three resistors are connected in parallel,
Then 1/R=1/2 +1/3 +1/6
R=1 ohm
If , 6 ohm and 3ohm resistors are connected in parallel and their equivalent resistor of resistance 2 ohm is connected to a
2 ohm resistor in series.Then net resistance is 2 ohm.
Similarly you can check other combinations also.
With the given resistances 2Ω , 3 Ω and 6 Ω,we can't obtain a total resistance of 2.5.
If the three resistors are connected in series,then R=2+3+6=11 ohm
If the three resistors are connected in parallel,
Then 1/R=1/2 +1/3 +1/6
R=1 ohm
If , 6 ohm and 3ohm resistors are connected in parallel and their equivalent resistor of resistance 2 ohm is connected to a
2 ohm resistor in series.Then net resistance is 2 ohm.
Similarly you can check other combinations also.
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