identify the subs oixed / reduced. mno2 + 4hl arrow mncl2 + cl2 +2h2o . fe2o3 +al arrow fe +al2o3. pbo +c arrow pb + co . cuo +h2 arrow cu +h2o.

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Solution

Oxidation is the gain of oxygen and reduction is the loss of oxygen.
The given reactions are:
$M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} +2 H_{2} O$
Here MnO₂ looses oxygen. So, MnO₂ is reduced and HCl is oxidized.

$F e_{2} O_{3} + 2 A l \to 2 F e + A l_{2} O_{3}$
Here Fe₂O₃ looses oxygen. So, Fe₂O₃ is reduced and Al is oxidized.

$P b O + C \to P b + C O$
Here PbO looses oxygen. So, PbO is reduced and C is oxidized.

$C u O + H_{2} \to C u + H_{2} O$
Here CuO looses oxygen. So, CuO is reduced and H₂ is oxidized.

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Similar questions

Find out the process of oxidation , reduction. And oxidising agent ,reducing agent from the following.

1. MnO₂ + 4HCL ➡ MnCl₂ + 2H₂O + Cl₂

2.H₂S + SO₂➡ S+ H₂O

3.CuO + C ➡ Cu + CO

Identify the substance oxidized, substance reduced, oxidising agent and reducing agent.
$M n O_{2}$ + $4 H C l$ $\to$ $M n {C l}_{2}$ + $2 H_{2} O$ + ${C l}_{2}$ .

Q. Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :

M n O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}

Q. In the following reactions, identify the oxidising agent and the reducing agent.

4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

Q. The angry Arjun carried some arrows for fighting with Bheeshm. With half the arrows, he cut down the arrows thrown by Bheeshm on him. Six arrows, he used to kill the rath driver of Bheeshm. With one arrow each he knocked down respectively the rath, flag and the bow of Bheeshm. Finally, with one more than four times the square root of arrows he laid Bheeshm unconscious on an arrow bed. Find the total number of arrows Arjun had.

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