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Standard XII

Chemistry

Grignard Reagents

if 20 gms of ...

Question

if 20 gms of CaCO3 is treated with 20 gms of hcl, how many grams of CO2 can be generated according to given equation: CaCO3 (s) +2HCl (aq) - CaCl2 (aq) +H2O (l) +CO2(g)

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Solution

Molecular mass of CaCO₃ = 100 g
Molecular mass of HCl = 36.5 g
100 g of CaCO₃ reacts with 73 g (36.5 x 2) of HCl to give 44 gram of CO₂ according to given equation.
20 gram of CaCO₃will react with 73/100 *20 g HCl = 14.6 g. HCl only to give CO₂. So the limiting reagent is CaCO₃.
Since 100 g CaCO₃ give 44 g CO₂
**therefore 20 g of CaCO₃ will give = 44/100 *20 = 8.8 g CO₂.**

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C a C O_{3} = 100 u, H C l = 36.5 u C O_{2} = 44 u)

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C a C O_{3} (s) + 2 H C l (a q) ⟶ C a C l_{2} (a q) + H_{2} O (l) + C O_{2} (g)

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

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Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

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