If a=(-5), b=4, c=(-3), Find the value of
(i) 2a - 3b
(ii) 3b - 2b (iii) 4a% 3c

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Solution

If

$a = - 5, b = 4, c = - 3, then (i) 2 a - 3 b = 2 (- 5) - 3 (4) = - 10 - 12 = - 22 (ii) 3 b - 2 b = 1 b or b = 4 (answer)$

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∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 c \end{matrix} ∣ ∣ ∣ ∣

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∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 c \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

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