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Question

if an object is projected with an initial speed of 10m/s at angle 30 to the horizontal,find the time at which it attains maximum height.[g=10m/s]

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Solution

Here initial speed u = 10 m/s
angle to the horizontal is 30
Time at which it attains maximum height

$t = \frac{u \sin (θ)}{g} = \frac{10 m / s \sin (30 °)}{10 m / s^{2}} = 0.5 s$

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