Question

if one root of quadratic equation x^2-5x+k=0 is 4 then find the value of k.

Answer 1

Hi!

Here is the answer to your query.

It is given that one of the roots is 4

Thus, if we substitute x for 4 we can find value of k.

∴ 4² – 5 × 4 + k = 0 [substituting x as 4]

⇒ 16 – 20 + k = 0

⇒ –4 + k = 0

⇒ k = 4

Thus, the value of k is 4.

Cheers!