If the maximum kinetic energy of the electrons emitted by a photocell is 4 eV, what is the stopping poential?
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Solution
Relation between kinetic energy in terms of stopping potential is given by:
K.E. = eV0
where e= charge on the electron.
V0= stopping potential
given kinetic energy of an electron is 4 eV.
To convert it into joule we multiply it by e. (As 1 eV = 1.6 X 10-19J)
therefore 4e = eVā0
V0= 4 volts
Hence stopping potential is 4 volts.