In a potentiometerarrangement, a cell of emf 1.25 V gives a balance point at 35.0 cmlength of the wire. If the cell is replaced by another cell and thebalance point shifts to 63.0 cm, what is the emf of the second cell?

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Solution

Emf of the cell, E₁= 1.25 V
Balance point of thepotentiometer, l₁= 35 cm
The cell is replaced byanother cell of emf E₂.
New balance point ofthe potentiometer, l₂ = 63 cm
Therefore, emf of thesecond cell is 2.25V.

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In a potentiometerarrangement, a cell of emf 1.25 V gives a balance point at 35.0 cmlength of the wire. If the cell is replaced by another cell and thebalance point shifts to 63.0 cm, what is the emf of the second cell?

Emf of the cell, E1= 1.25 VBalance point of thepotentiometer, l1= 35 cmThe cell is replaced byanother cell of emf E2.New balance point ofthe potentiometer, l2 = 63 cmTherefore, emf of thesecond cell is 2.25V.

Emf of the cell, E₁= 1.25 V
Balance point of thepotentiometer, l₁= 35 cm
The cell is replaced byanother cell of emf E₂.
New balance point ofthe potentiometer, l₂ = 63 cm
Therefore, emf of thesecond cell is 2.25V.