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Question

In the following redox reaction,

Cr2O2−7+Fe2+⟶Fe3++Cr3+Cr2O72+Fe2+⟶Fe3++Cr3+

1 mole of Cr2O2− C r 2 O 7 2 −oxidises how many moles of fe

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Solution

Dear Student,

Cr2O72- + Fe2+ Fe3+ + Cr3+Balancing the equation in acidic mediumStep 1: Write the two half reactionsOxidation : Fe2+ Fe3+Reduction : Cr2O72- Cr3+Step 2:Balance all atoms other than H and OOxidation : Fe2+ Fe3+Reduction : Cr2O72- 2Cr3+Step 3: Balance O by adding H2OOxidation : Fe2+ Fe3+Reduction : Cr2O72- 2Cr3+ + 7H2OStep 4: Balance H by adding H+Oxidation : Fe2+ Fe3+Reduction : Cr2O72- +14H+ 2Cr3+ + 7H2OStep 5: Balance charge by adding electronsOxidation : Fe2+ Fe3+ +e-Reduction : Cr2O72- +14H++6e- 2Cr3+ + 7H2OStep 6: Multiply oxidation half by 6 and add both equationsCr2O72- +14H++6Fe2+ 2Cr3+ + 6Fe3+ +7H2OFrom the above balanced equation, we can see that 1 mol of Cr2O72- oxidised 6 mol of Fe2+.

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