wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let us assume in a given plant the genotype symbol "Y" stands for dominant yellow seed colour and "y" for recessive green seeds colour symbol "R" for round seed shape and "r" for wrinkled seeds. Two homozygous parents (plants) with genotypes "RRYY" and "rryy" are crossed and their F1 generation progeny is then selfed. What shall be the

a) Phenotype of F1 progeny

b) Genotype of F1 progeny

c) Gemete genotype of F1 progeny

d) Phenotypic ratio of F2 population

e) Phenotypic ratio of yellow seed to green and round seed to wrinkled seed in F2 population.

Open in App
Solution

(a) Phenotype of F1 progeny will be round seed shape and yellow seed colour.
(b) Genotype of F1 progeny will be RrYy.
(c) Gamete genotype of F1 progeny will be RY, Ry, rY, ry.
(d) Phenotypic ratio of F2 population = 9:3:3:1
(e) Phenotypic ratio of yellow seed to green seed and round seed to wrinkled seed in F2 population = 3:1 (for both)

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rediscovery of Mendelism
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon