Mendel selected two kinds of pea plants for his experiment, namely those that always gave tall plants and those that always gave short plants. He then obtained progeny F1 from tall and short parental plants. He selfed the F1 and obtained the F2 progeny. Write and explain the results of F1 and F2 progeny obtained by Mendel.
Mendel selected two kinds of pea plants for his experiment, namely those that always gave tall plants and those that always gave short plants. He then obtained progeny F1 from tall and short parental plants. He selfed the F1 and obtained the F2 progeny. Write and explain the results of F1 and F2 progeny obtained by Mendel.
Dear Student,
In the given question, Mendel selected two types of plants. Let us take the dominant allele (tall) for plant height as 'T' and the recessive allele (short) as 't'
The plant which always gave tall plants will be homozygous dominant, therefore, its genotype will be TT. The plant which always gave short plants will be homozygous recessive, therefore, its genotype will be tt. So, the cross would be as follows:
Parents: TT x tt
Gametes: T , t
F1 generation: Tt
All the plants of the F1 generation will be heterozygous tall (Tt).
F2 generation: Tt x Tt
T t T TT Tt t Tt tt
So, the phenotypic ratio of the given cross is tall:short :: 3:1. Out of the four plants three will be tall and one will be short.
Genotypic ratio of the given cross 1:2:1 :: TT:Tt:tt. Out of the four plants one will be homozygous tall (TT), two will be heterozygous tall (Tt) and one will be homozygous short (tt).
Dear Student,
In the given question, Mendel selected two types of plants. Let us take the dominant allele (tall) for plant height as 'T' and the recessive allele (short) as 't'
The plant which always gave tall plants will be homozygous dominant, therefore, its genotype will be TT. The plant which always gave short plants will be homozygous recessive, therefore, its genotype will be tt. So, the cross would be as follows:
Parents: TT x tt
Gametes: T , t
F1 generation: Tt
All the plants of the F1 generation will be heterozygous tall (Tt).
F2 generation: Tt x Tt
| T | t | |
| T | TT | Tt |
| t | Tt | tt |
So, the phenotypic ratio of the given cross is tall:short :: 3:1. Out of the four plants three will be tall and one will be short.
Genotypic ratio of the given cross 1:2:1 :: TT:Tt:tt. Out of the four plants one will be homozygous tall (TT), two will be heterozygous tall (Tt) and one will be homozygous short (tt).
