Methane is heated strongly in air to undergo complete combustion. calculate the no. of moles and amount of carbon dioxide formed when 6x102 molecules of methane burn
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Solution
Reaction Involved-
CH4+ 2O2→ CO2+ 2H2O
1 mol of CH4reacts with 2 mol of O2 to produce 1 mol of CO2
Thus,6.022 x 1023 molecules of CH4= 6.022 x 1023 molecules of CO2
Thus,
6 x102molecules of CH4 = 6x102molecules of CO2
6x102molecules of CO2= 6 x 102/ 6.022 x 10 23 mol = 9.9 x 10-24 mol
Amount of CO2produced
= (Moles) x (Molar mass)
= 9.9 x 10-24 mol x 44 g/mol = 435.6 x 10-24 g