N factor for the reaction (BrO3-) + (Br-)= Br2

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Solution

n factor = no of atoms * change in oxidation number
Change in oxidation number in the given equation is -4 and 2 atoms are involved in the reaction
Therefore:
n factor = -4 * 2
= -8

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B r_{2} + O H^{-} \to B r^{-} + B r O_{3}^{-} + H_{2} O

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{B r}_{2} + {O H}^{-} ⟶ B r O_{3}^{-} + {B r}^{-} + H_{2} O

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