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Gram Atomic Mass

O2 and SO2 ga...

Question

O2 and SO2 gases are filled in ratio of 1:3 by moles in a closed container of 3L at temp of 27 degC . the partial pressure of O2 is 0.60atm , the concentration of SO2 would be :
ans: 0.036

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Solution

Here.molar ratio = 1:3
So, mole fraction of O₂ = 1/4 = 0.25
Mole fraction of SO₂ = 1-0.25 = 0.75
The partial pressure of O₂ gas, p = mole fraction x total pressure.
Hence, total pressure = p/ mole fraction = 0.60/0.25 = 2.4 atm
So, partial pressure of SO₂ = 2.4-0.60 = 1.8 atm
We kn ow, for a particular gas,
PV = nRT
Hence, n/V= P/RT
Or,Concentration =n/V
In case of SO₂ , P = 1.8 atm T = 300 K, R = 0.0821 Latm/Kmol
Hence, C = n/V = P/RT
Or, C = 1.8 /(0.0821 x300) = 0.073

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