Question

[P] on treatment with ${\mathrm{Br}}_2$ / ${\mathrm{FeBr}}_3$ in ${\mathrm{CCl}}_4$ produced a single isomer ${\mathrm{C}}_8{\mathrm{H}}_7{\mathrm{O}}_2\mathrm{Br}$ while heating [P] with soda lime gave toluene. The compound [P] is:

• A.

  

• B.

  

• C.

  

• D.

  

Answer 1

The correct option is B

The explanation for the correct option:

Option (B):

1. $4-$methyl benzoic acid or Toluic acid on reaction with ${\mathrm{Br}}_2$ gives $3-$Bromo $4-$methyl benzoic acid.
2. $4-$methyl benzoic acid or Toluic acid on reaction with soda lime undergoes decarboxylation resulting in the formation of toluene.

Therefore, the compound P is