1. A circular path of radius 20m is covered in one minute. With what average speed the track can be covered?

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Solution

$T o t a l d i s t n a c e t r a v e l l e d w i l l b e s a m e a s t h e c i r c u m f r e n c e o f t h e c i r c l e = 2 π r D = 2 \times 3.14 \times 20 = 125.6 m t o t a l t i m e t a k e n = 1 m i n = 60 s e c o n d A v e r a g e = \frac{125.6}{60} = 2.09 m / s$

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1. A circular path of radius 20m is covered in one minute. With what average speed the track can be covered?

Total distnace travelled will be same as the circumfrence of the circle = 2πrD = 2×3.14×20 = 125.6 mtotal time taken = 1 min = 60 secondAverage = 125.660 = 2.09 m/s

$T o t a l d i s t n a c e t r a v e l l e d w i l l b e s a m e a s t h e c i r c u m f r e n c e o f t h e c i r c l e = 2 π r D = 2 \times 3.14 \times 20 = 125.6 m t o t a l t i m e t a k e n = 1 m i n = 60 s e c o n d A v e r a g e = \frac{125.6}{60} = 2.09 m / s$