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Converse of Theorem 2

PQRS and PABC...

Question

PQRS and PABC are two parallelograms of equal area. Prove that QC is parallel to BR.

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Solution

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PQRS and ABRS are parallelograms and X is any point on side BR. Then, ar(parallelogram PQRS) is equal to

Q. Prove that the two parallelogram on the same base and between two parallels are equal in area

P Q R S

A B R S

are parallelogram and

X

is any point on side

B R

a r e a (P Q R S) = a r e a (A B R S)

a r e a (A X S) = \frac{1}{2} a r e a (P Q R S)

Q. Prove that parallelograms are on the same base and between the same parallel lines are equal in area.

P Q R S

A B R S

are parallelograms and

X

is any point on the side

B R

a r (P Q R S) = a r (A B R S)

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Converse of Theorem 2

Standard IX Mathematics

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