Question

solve the following equation:

5y-4/8-y-3/5=y+6/4

(answer=8)

Answer 1

$$\begin{gathered} \frac{5y-4}{8}-\frac{y-3}{5}=\frac{y+6}{4} \\ \Rightarrow \frac{5\left(5y-4\right)-8\left(y-3\right)}{40}=\frac{y+6}{4} \\ \Rightarrow \frac{25y-20-8y+24}{40}=\frac{y+6}{4} \\ \Rightarrow \frac{17y+4}{40}=\frac{y+6}{4} \\ \Rightarrow 4\left(17y+4\right)=40\left(y+6\right) \\ \Rightarrow 68y+16=40y+240 \\ \Rightarrow 68y-40y=240-16 \\ \Rightarrow 28y=224 \\ \Rightarrow y=\frac{224}{28}=8 \end{gathered}$$