Solve the following equations-a- 3x-5x-2- -4-b- 2m-1-3m-5-8-0-c- 3x-4-6x-7-x-1-2x-3

A) #160;3x5x+2 #160;= #160; 4 #8658;3x #160;= #160; 45x+2 #8658;3x= 20x 8 #8658;3x+20x #160;= #160; 8 #8658;23x #160;= #160; 8 #8658 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Solving an Equation Using Transposition

Solve the fol...

Question

Solve the following equations:
(a) 3x/5x+2= -4
(b) 2m/1-3m+5/8=0

Open in App

Solution

a) 3x5x+2 = -4
⇒3x = -45x+2
⇒3x=-20x8
⇒3x+20x = -8
⇒23x = -8
⇒x = -823
b) 2m1-3m+58 = 0
⇒2m1-3m = -58
⇒2m×8 = -51-3m
⇒16m = -5+15m
⇒16m-15m = -5⇒m = -5

Suggest Corrections

Similar questions

Q. Solve the following equation
(a)

5 x - 11 = 2 x + 7

(b)

3 (x - 8) - 2 (x - 5) = 2 - 5 x

(c)

2 (3 x + 1) - 7 = 2 (6 x - 7)

Q. Solve the following equations:
(a)

x - 5 = 7

(b)

3 x + 18 = 48

(c)

2 x = 48

(d)

5 (x - 1) + 3 = 23

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$