Question

6. A force of 10N acting on a body at an angle of 600 with the horizontal direction displaces the body through a distance of 2m along the surface of a floor. Calculate the work done. Now let the force or pulling act on the body makes an angle of 300 with the horizontal. What is the value of the force to displace the body through 2m along the surface of the floor?

Answer 1

First case:

Force, F = 10 N

Angle with horizontal, θ = 60^o

Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is = F cosθ = (10)(cos60) = 5 N

So, work done is, W = (5)(2) = 10 J

Second case:

Force, F = ?

Angle with horizontal, θ = 30^o

Displacement in horizontal direction, S = 2 m

Component of force along horizontal direction is = F cosθ = (F)(cos30) = F(√3/2) N

Any non-zero value of force will cause a displacement of 2 m.