Show that the force on each plate of a parallel plate capacitor has a magnitude of ½QE. Where Q in charge on capacitor and E is the field between the plates
Here we can consider the capacitor plates as infinitely charged planes having uniform distributions.
now, the force of attraction on a plate of area A due to influence of another plate of equal area would be
F = σ2A / 2ε0
or
F = (1/2).(σ/ε0).(σA)
now, in this case we know that
E = σ/ε0
Q = σA
thus,
F = (1/2).E.Q
or
F = (1/2)QE