Two identical resistors , each of resistance 10ohm are connected
( i) in series
(ii) in parallel , in turns to a battery of 6 volt
CAlculate the ratio of power consumed in the combination of resistors in two cases

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Solution

Here,
R₁ = 10Î©
R₂ = 10Î©
V = 6 volts
Eqv. resistance in series combination = 10 + 10
R_s = 20Î©
P_s = V²/R_s
= 6²/20
= 36/20 W
Eqv. resistance in parallel combination = 10Ã—10/(10+10)
R_p = 5Î©
P_p = V²/R_p
= 6²/5
= 36/5 W

P_p/P_s = (36/20)/(36/5)
= 1/4
P_p:P_s = 1:4

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Two identical resistors , each of resistance 10ohm are connected( i) in series(ii) in parallel , in turns to a battery of 6 voltCAlculate the ratio of power consumed in the combination of resistors in two cases

Here,R1 = 10Î©R2 = 10Î©V = 6 voltsEqv. resistance in series combination = 10 + 10 Rs = 20Î©Ps = V2/Rs = 62/20 = 36/20 W Eqv. resistance in parallel combination = 10Ã—10/(10+10) Rp = 5Î©Pp = V2/Rp = 62/5 = 36/5 W Pp/Ps = (36/20)/(36/5) = 1/4Pp:Ps = 1:4

Two identical resistors , each of resistance 10ohm are connected
( i) in series
(ii) in parallel , in turns to a battery of 6 volt
CAlculate the ratio of power consumed in the combination of resistors in two cases

Here,
R₁ = 10Î©
R₂ = 10Î©
V = 6 volts
Eqv. resistance in series combination = 10 + 10
R_s = 20Î©
P_s = V²/R_s
= 6²/20
= 36/20 W
Eqv. resistance in parallel combination = 10Ã—10/(10+10)
R_p = 5Î©
P_p = V²/R_p
= 6²/5
= 36/5 W

P_p/P_s = (36/20)/(36/5)
= 1/4
P_p:P_s = 1:4