Question

standing waves are produced in 10m long stretched string fixed at both ends. If the string vibrates in 5 segments and wave velocity is 20m/s the frequency is

1- 5hz

2-10hz

3-2hz

4-4Hz

Answer 1

Given,
Total length of string=10 m
Number of segments=5
Then,
Wavelength is given by
$$\begin{gathered} =2\times \frac{10}{5}=4 \\ \mathrm{Now},\mathrm{using} \\ \mathrm{v}=\mathrm{f\lambda } \\ \mathrm{f}=\frac{\mathrm{v}}{\mathrm{\lambda }}=\frac{20}{4}=5\mathrm{Hz} \end{gathered}$$